What is the domain of f(x)= 1/(sqrt(4-2x)) ?

The domain of f(x)= 1/(sqrt(4-2x)) is x<2

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domain of f(x)= 1/(sqrt(4-2x))

domain

f (x) = \frac{1}{4 - 2 x}

x < 2

Interval Notation

(- \infty, 2)

Solution steps

Find non-negative values for radicals:

x \leq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x < 2

\frac{( - 2 x - 7 )}{9 x - 5}

f (x) = 6 x - 52 x - 9

(x + 7)^{3} + 2

f (x) = \frac{1}{2 x + 11}

f (x) = \frac{1}{9 x ^{2} + 69 x + 130}

What is the domain of f(x)= 1/(sqrt(4-2x)) ?
The domain of f(x)= 1/(sqrt(4-2x)) is x<2