What is the domain of f(x)=log_{3}(2+6x) ?

The domain of f(x)=log_{3}(2+6x) is x>-1/3

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domain of f(x)=log_{3}(2+6x)

domain

f (x) = lo g_{3} (2 + 6 x)

x > - \frac{1}{3}

Interval Notation

(- \frac{1}{3}, \infty)

Solution steps

Find positive values for logs:

x > - \frac{1}{3}

The function domain

x > - \frac{1}{3}

f (x) = \frac{x}{x ^{2} + 6}

\frac{x + 6}{x ^{2} - 4}

3^{x} + 2

\frac{4}{1 - 3 ( \frac{1}{x} )}

f (x) = \frac{( x + 4 )}{- ( x - 1 ) - 1}

What is the domain of f(x)=log_{3}(2+6x) ?
The domain of f(x)=log_{3}(2+6x) is x>-1/3