What is the domain of y=((x+1)^3)/((x-1)^2) ?

The domain of y=((x+1)^3)/((x-1)^2) is x 1

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domain of y=((x+1)^3)/((x-1)^2)

domain

y = \frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (3) = x + 1 + 4

f (x) = \frac{∣ x ∣}{x ^{2} - 9}

f (x) = 8.9 x + 8.3

f (x) = \frac{( x ^{2} - 4 x + 4 )}{( x + 2 )}

f (x) = x y^{2} + x y - 6 x - 3 = 0

What is the domain of y=((x+1)^3)/((x-1)^2) ?
The domain of y=((x+1)^3)/((x-1)^2) is x<1\lor x>1