What is the domain of f(x)=ln(2e^x-1) ?

The domain of f(x)=ln(2e^x-1) is x>-ln(2)

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domain of f(x)=ln(2e^x-1)

domain

f (x) = ln (2 e^{x} - 1)

x > - ln (2)

Interval Notation

(- ln (2), \infty)

Solution steps

Find positive values for logs:

x > - ln (2)

The function domain

x > - ln (2)

\frac{1}{3 x + 1}

f (x) = \frac{x ^{2} - 16}{x ^{2} - 3 x}

f (x) = sin (x) + x

f (x) = lo g_{10} (2 x - 200)

f (x) = x^{3} - 5 x^{2} + 6 x

What is the domain of f(x)=ln(2e^x-1) ?
The domain of f(x)=ln(2e^x-1) is x>-ln(2)