What is the domain of f(x)= 1/((x-1)(x+3)) ?

The domain of f(x)= 1/((x-1)(x+3)) is x 1

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domain of f(x)= 1/((x-1)(x+3))

domain

f (x) = \frac{1}{( x - 1 ) ( x + 3 )}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 3

The function domain

x < - 3 or - 3 < x < 1 or x > 1

f (x) = \frac{x - 4}{x - 1 + 2}

f (x) = 5^{2 x - 1} - 2

x^{3} + 2 x - 3

f (x) = \frac{3 x ( x + 3 )}{( x - 2 ) ( x - 5 )}

9 x - 3

What is the domain of f(x)= 1/((x-1)(x+3)) ?
The domain of f(x)= 1/((x-1)(x+3)) is x<-3\lor-3<x<1\lor x>1