What is the domain of f(x)=sqrt(36-x^2)-sqrt(x+2) ?

The domain of f(x)=sqrt(36-x^2)-sqrt(x+2) is -2<= x<= 6

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domain of f(x)=sqrt(36-x^2)-sqrt(x+2)

domain

f (x) = 36 - x^{2} - x + 2

- 2 \leq x \leq 6

Interval Notation

[- 2, 6]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 6

The function domain

- 2 \leq x \leq 6

f (x) = \frac{x - 7}{x - 5}, x < 7

7 - 4 x

f (x) = lo g_{10} (\frac{1}{2}) (4 - ∣ x ∣)

f (x) = \frac{x ^{3}}{x - 2}

\frac{7}{x ( x - 5 )}

What is the domain of f(x)=sqrt(36-x^2)-sqrt(x+2) ?
The domain of f(x)=sqrt(36-x^2)-sqrt(x+2) is -2<= x<= 6