What is the domain of sin(x)2cos(x)-1,0<= x<= 2pi ?

The domain of sin(x)2cos(x)-1,0<= x<= 2pi is 0<= x<= 2pi

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domain of sin(x)2cos(x)-1,0<= x<= 2pi

domain

sin (x) 2 cos (x) - 1, 0 \leq x \leq 2 π

0 \leq x \leq 2 π

Interval Notation

[0, 2 π]

Solution steps

Set the domain to the given interval

0 \leq x \leq 2 π

The function has no undefined points nor domain constraints. Therefore, the domain is

0 \leq x \leq 2 π

x - 2 x^{2} - 6

f (x) = 7 x - 9

- \frac{3}{2} x + 1

f (x) = \frac{ln ( x + 1 )}{e ^{x} - 1}

f (x) = x 6 - x

What is the domain of sin(x)2cos(x)-1,0<= x<= 2pi ?
The domain of sin(x)2cos(x)-1,0<= x<= 2pi is 0<= x<= 2pi