What is the amplitude of f(x)=-4sin(12x-pi/4)+3 ?

The amplitude of f(x)=-4sin(12x-pi/4)+3 is 4

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amplitude of f(x)=-4sin(12x-pi/4)+3

amplitude

f (x) = - 4 sin (12 x - \frac{π}{4}) + 3

4

Solution steps

f (x) = - 4 sin (12 x - \frac{π}{4}) + 3, A = - 4

Therefore, the amplitude |A| is

4

4

f (x) = 5 (x + 2)

f (x) = \frac{5 - x}{5 + x}

f (x) = \frac{x ^{2} - 9}{4 x ^{2}}, x > 0

2 x = 10 - 3 y

f (x) = 16 x^{2}

What is the amplitude of f(x)=-4sin(12x-pi/4)+3 ?
The amplitude of f(x)=-4sin(12x-pi/4)+3 is 4