What is the domain of sqrt(4\sqrt{(4x^2-3))-3} ?

The domain of sqrt(4\sqrt{(4x^2-3))-3} is x = (sqrt(57))/8

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domain of sqrt(4\sqrt{(4x^2-3))-3}

domain

4 (4 x^{2} - 3) - 3

x \leq - \frac{57}{8} or x \geq \frac{57}{8}

Interval Notation

(- \infty, - \frac{57}{8}] \cup [\frac{57}{8}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{57}{8} or x \geq \frac{57}{8}

The function domain

x \leq - \frac{57}{8} or x \geq \frac{57}{8}

\frac{4 x}{5 x - 6}

f (x) = 7 x - 3

f (x) = \frac{x}{x ^{2} - 4 x - 12}

lo g_{10} (6) (x^{2} - 16)

f (x) = \frac{x + 4}{x + 3}

What is the domain of sqrt(4\sqrt{(4x^2-3))-3} ?
The domain of sqrt(4\sqrt{(4x^2-3))-3} is x<=-(sqrt(57))/8 \lor x>= (sqrt(57))/8