What is the domain of y=(sqrt(2+x))/(3-x) ?

The domain of y=(sqrt(2+x))/(3-x) is -2 3

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domain of y=(sqrt(2+x))/(3-x)

domain

y = \frac{2 + x}{3 - x}

- 2 \leq x < 3 or x > 3

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 2 \leq x < 3 or x > 3

- x^{2} - 6 x + 9

y = - \frac{3}{x - 1}

f (x) = 5 \cdot 3^{x}

f (x) = \frac{3 x}{x ^{2} + 3}

y = 3 \cdot 5^{x}

What is the domain of y=(sqrt(2+x))/(3-x) ?
The domain of y=(sqrt(2+x))/(3-x) is -2<= x<3\lor x>3