What is the domain of y=sqrt(3x+4) ?

The domain of y=sqrt(3x+4) is x>=-4/3

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domain of y=sqrt(3x+4)

domain

y = 3 x + 4

x \geq - \frac{4}{3}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - \frac{4}{3}

The function domain

x \geq - \frac{4}{3}

y = (\frac{2}{3})^{x}

f (x) = \frac{4}{x - 6} + \frac{4}{x - 1}

f (x) = 8 x^{- \frac{29}{12}}, x > 0

3 t^{3}

f (x) = (x - 1) (x - 2)