What is the domain of (8x-12)/(4+3x) ?

The domain of (8x-12)/(4+3x) is x -4/3

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domain of (8x-12)/(4+3x)

domain

\frac{8 x - 12}{4 + 3 x}

x < - \frac{4}{3} or x > - \frac{4}{3}

Interval Notation

(- \infty, - \frac{4}{3}) \cup (- \frac{4}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{4}{3}

The function domain

x < - \frac{4}{3} or x > - \frac{4}{3}

y = \frac{3 x ^{2} + 5 x + 9}{x ^{2} - 25}

3 x^{2} - 30 x + 77

(x - 1) + (4 x^{2})

f (x) = ∣ x + 2 ∣ + 4, - 5 \leq x \leq 2

f (x) = \frac{1}{64 - 25 x ^{2}}

What is the domain of (8x-12)/(4+3x) ?
The domain of (8x-12)/(4+3x) is x<-4/3 \lor x>-4/3