What is the domain of (sqrt(2x+5))/(sqrt(x^3-8)) ?

The domain of (sqrt(2x+5))/(sqrt(x^3-8)) is x>2

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domain of (sqrt(2x+5))/(sqrt(x^3-8))

domain

\frac{2 x + 5}{x ^{3} - 8}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

\frac{2}{r ^{2} + 1}

f (x) = 4 x^{2} + 7

f (x) = - 3 (x + 7) - 7

4 x^{3} - 12 x^{2}

y = - 2 - x + 1

What is the domain of (sqrt(2x+5))/(sqrt(x^3-8)) ?
The domain of (sqrt(2x+5))/(sqrt(x^3-8)) is x>2