What is the domain of f(x)= x/(1-e^{x^2-9)} ?

The domain of f(x)= x/(1-e^{x^2-9)} is x 3

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domain of f(x)= x/(1-e^{x^2-9)}

domain

f (x) = \frac{x}{1 - e ^{x^{2} - 9}}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

\frac{1}{2} - \frac{1}{2} cos (2 x - \frac{π}{4})

\frac{15 x - 15}{x ^{2} + 3 x - 4}

ln (\frac{x + 1}{x - 2})

f (x) = x^{4} + 4 x^{3} + 1

g (x) = \frac{2}{2 + 4 x ^{2}}

What is the domain of f(x)= x/(1-e^{x^2-9)} ?
The domain of f(x)= x/(1-e^{x^2-9)} is x<-3\lor-3<x<3\lor x>3