What is the domain of 1/(x^2+3x-4) ?

The domain of 1/(x^2+3x-4) is x 1

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domain of 1/(x^2+3x-4)

domain

\frac{1}{x ^{2} + 3 x - 4}

x < - 4 or - 4 < x < 1 or x > 1

Interval Notation

(- \infty, - 4) \cup (- 4, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 4

The function domain

x < - 4 or - 4 < x < 1 or x > 1

f (x) = - x^{2} - 5

- 2 x^{2} + 30 x - 100

5^{x} - 8

f (x) = 4 x + 2 x^{3} + (x^{2} + 2 x)

f (x) = \frac{x - 2}{x + 2}

What is the domain of 1/(x^2+3x-4) ?
The domain of 1/(x^2+3x-4) is x<-4\lor-4<x<1\lor x>1