en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=-(x+2)^2+4

Solution

range

f (x) = - (x + 2)^{2} + 4

Solution

f (x) \leq 4

+1

Interval Notation

(- \infty, 4]

Solution steps

Vertex of

- (x + 2)^{2} + 4 :

Maximum

(- 2, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (- 2, 4)

f (x) \leq 4

Popular Examples

asymptotes of (x^2-9)/(x^3-2x^2-15x)asymptotes

\frac{x ^{2} - 9}{x ^{3} - 2 x ^{2} - 15 x}

asymptotes of f(x)=(3x^2)/(2x^2-32)asymptotes

f (x) = \frac{3 x ^{2}}{2 x ^{2} - 32}

inverse of y=(4x-2)/(3x+1)inverse

y = \frac{4 x - 2}{3 x + 1}

frequency f(x)= 1/2 cos(2x)frequency

f (x) = \frac{1}{2} cos (2 x)

domain of f(t)=17-1.2t domain

f (t) = 17 - 1.2 t

Frequently Asked Questions (FAQ)

What is the range of f(x)=-(x+2)^2+4 ?
The range of f(x)=-(x+2)^2+4 is f(x)<= 4