What is the domain of f(0)=sqrt(x-1) ?

The domain of f(0)=sqrt(x-1) is x>= 1

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domain of f(0)=sqrt(x-1)

domain

f (0) = x - 1

x \geq 1

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

\frac{x + 5}{2} + 3

f (x) = \frac{x + 4}{x ^{2} - x - 6}

f (x) = 3 - x - 2

f (x) = 3 - x - 1

\frac{x - 5}{x - 8}