What is the domain of y=sqrt(5(x-4)+45) ?

The domain of y=sqrt(5(x-4)+45) is x>=-5

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domain of y=sqrt(5(x-4)+45)

domain

y = 5 (x - 4) + 45

x \geq - 5

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 5

The function domain

x \geq - 5

f (x) = x^{2} - 8 x - 7

\frac{1}{x - 1} - 3

x^{2} - 18 x + 82

f (x) = \frac{x ^{3} + 2 x ^{2} - 15 x}{18 x - 2 x ^{3}}

y = 2 x - 3

What is the domain of y=sqrt(5(x-4)+45) ?
The domain of y=sqrt(5(x-4)+45) is x>=-5