What is the domain of f(x)=\sqrt[3]{x-3}+(3x)/(x-2) ?

The domain of f(x)=\sqrt[3]{x-3}+(3x)/(x-2) is x 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=\sqrt[3]{x-3}+(3x)/(x-2)

domain

f (x) = 3 x - 3 + \frac{3 x}{x - 2}

x < 2 or x > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2

The function domain

x < 2 or x > 2

f (x) = ∣ 2 - x ∣ - 3, - 3 < x \leq 0

f (x) = \frac{1 - x}{2 x - 1}

f (x) = x + 2 + 2

\frac{48}{( x + 1 ) ^{2}} + \frac{4}{x + 1} + 1

f (x) = e^{- 8 x}

What is the domain of f(x)=\sqrt[3]{x-3}+(3x)/(x-2) ?
The domain of f(x)=\sqrt[3]{x-3}+(3x)/(x-2) is x<2\lor x>2