What is the domain of f(x)=((x+9))/((x^2-81)) ?

The domain of f(x)=((x+9))/((x^2-81)) is x 9

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domain of f(x)=((x+9))/((x^2-81))

domain

f (x) = \frac{( x + 9 )}{( x ^{2} - 81 )}

x < - 9 or - 9 < x < 9 or x > 9

Interval Notation

(- \infty, - 9) \cup (- 9, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = - 9

The function domain

x < - 9 or - 9 < x < 9 or x > 9

f (x) = \frac{4 x ^{2} + 4}{∣ 2 x ^{2} - 8 ∣}

f (x) = \frac{( 1 + x )}{e ^{c o s (x)}}

(x - 1) (2 x + 1) (x - 3) (x + 4)

y = 2 (x + 5) - 2

- \frac{3 x + 3}{2}

What is the domain of f(x)=((x+9))/((x^2-81)) ?
The domain of f(x)=((x+9))/((x^2-81)) is x<-9\lor-9<x<9\lor x>9