What is the domain of y=x^2+8 ?

The domain of y=x^2+8 is -infinity <x<infinity

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domain of y=x^2+8

domain

y = x^{2} + 8

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 3 x^{3} - 14 x^{2} - 5 x

f (x) = \frac{3 x - 6}{x ^{2} + 5 x - 104}

f (x) = 7 x - 2

f (x) = - (\frac{1}{2})^{2} - x

y = \frac{4}{x ^{2} - 4}