What is the domain of y=sqrt((x-1)/(x+1)) ?

The domain of y=sqrt((x-1)/(x+1)) is x = 1

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domain of y=sqrt((x-1)/(x+1))

domain

y = \frac{x - 1}{x + 1}

x < - 1 or x \geq 1

Interval Notation

Solution steps

Find non-negative values for radicals:

x < - 1 or x \geq 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x \geq 1

6 x^{2} + 6 x - 36

2 x^{2} + x - 14

f (x) = - x^{2} + 2 x - 3

lo g_{4} (x^{2} - 4)

f (x) = lo g_{x} (2)

What is the domain of y=sqrt((x-1)/(x+1)) ?
The domain of y=sqrt((x-1)/(x+1)) is x<-1\lor x>= 1