What is the domain of y=(x+4)^2-5/2 ?

The domain of y=(x+4)^2-5/2 is -infinity <x<infinity

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domain of y=(x+4)^2-5/2

domain

y = (x + 4)^{2} - \frac{5}{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = \frac{1}{3} e^{x - 2} + 2

f (x) = 4 x - 5 + 1

f (x) = sin (3 t)

f (x) = - 2 (x - 3)^{2} + 7

v (x) = 6 - x

What is the domain of y=(x+4)^2-5/2 ?
The domain of y=(x+4)^2-5/2 is -infinity <x<infinity