What is the domain of y=(x+4)/(sqrt(x^2-3)) ?

The domain of y=(x+4)/(sqrt(x^2-3)) is x sqrt(3)

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domain of y=(x+4)/(sqrt(x^2-3))

domain

y = \frac{x + 4}{x ^{2} - 3}

x < - 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x > 3

f (x) = ln (\frac{2 - x}{x + 2})

f (x) = \frac{7}{4 x + 2}

f (x) = \frac{6 - 8 x}{x - 9}

f (x) = \frac{3 x}{4}

f (x) = \frac{1}{ln ( x ) x ^{2} + 2 x}

What is the domain of y=(x+4)/(sqrt(x^2-3)) ?
The domain of y=(x+4)/(sqrt(x^2-3)) is x<-sqrt(3)\lor x>sqrt(3)