What is the domain of f(x)=3+sqrt(x-2) ?

The domain of f(x)=3+sqrt(x-2) is x>= 2

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domain of f(x)=3+sqrt(x-2)

domain

f (x) = 3 + x - 2

x \geq 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = e^{4 x}

f (x) = 3 x^{2} - 5 x

\frac{( x - 7 ) ^{2} ( 5 - x )}{x + 1 - 1}

f (x) = \frac{1}{1 - 2 cos ( x )}

F (x) = 10 x + 4

What is the domain of f(x)=3+sqrt(x-2) ?
The domain of f(x)=3+sqrt(x-2) is x>= 2