What is the domain of f(x)=(2x^2+10x+8)/(x-2) ?

The domain of f(x)=(2x^2+10x+8)/(x-2) is x 2

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domain of f(x)=(2x^2+10x+8)/(x-2)

domain

f (x) = \frac{2 x ^{2} + 10 x + 8}{x - 2}

x < 2 or x > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2

The function domain

x < 2 or x > 2

f (x) = \frac{x}{∣ x ∣ + 1}

\frac{5 + 7 x}{x - 1}

f (x) = \frac{( x + 4 )}{( x ^{2} - 16 )}

f (x) = \frac{5}{x - 3} + x^{2} - 3 x - 28

f (x) = \frac{x}{x ^{2} + 7 x + 12}

What is the domain of f(x)=(2x^2+10x+8)/(x-2) ?
The domain of f(x)=(2x^2+10x+8)/(x-2) is x<2\lor x>2