What is the domain of y=(x+1)/(sqrt(x)) ?

The domain of y=(x+1)/(sqrt(x)) is x>0

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domain of y=(x+1)/(sqrt(x))

domain

y = \frac{x + 1}{x}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

f (x) = 3 x + 2 - 1

V (x) = 4 x^{3} - 100 x^{2} + 600 x

f (x) = x^{3} - 6 x^{2}

f (x) = - 5 x^{4} - x^{3} + 22 x^{2} + 4 x - 8

3 \cdot x^{\frac{2}{3} - 2 x}

What is the domain of y=(x+1)/(sqrt(x)) ?
The domain of y=(x+1)/(sqrt(x)) is x>0