What is the domain of f(x)= 1/(\sqrt[4]{x^2-5)} ?

The domain of f(x)= 1/(\sqrt[4]{x^2-5)} is x sqrt(5)

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domain of f(x)= 1/(\sqrt[4]{x^2-5)}

domain

x < - 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

Find undefined (singularity) points:

x = 5, x = - 5

Combine real regions and undefined points for final function domain

x < - 5 or x > 5

x^{2} - 8 x - 9

f (x) = \frac{1}{3} - 2 x

f (x) = - 2 x (x - 2) (x - 6)

f (x) = \frac{- 10}{5 + x}

2 π

What is the domain of f(x)= 1/(\sqrt[4]{x^2-5)} ?
The domain of f(x)= 1/(\sqrt[4]{x^2-5)} is x<-sqrt(5)\lor x>sqrt(5)