What is the domain of f(x)=sqrt(x^4-1) ?

The domain of f(x)=sqrt(x^4-1) is x = 1

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domain of f(x)=sqrt(x^4-1)

domain

f (x) = x^{4} - 1

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

f (x) = sin (x) + \frac{1}{2}

y = sin (e^{- t})

f (x) = \frac{1}{x - 81}

f (x) = 2 x^{3} - 6 x^{2} + 4

f (x) = 4 x^{2} - 12 x + 8

What is the domain of f(x)=sqrt(x^4-1) ?
The domain of f(x)=sqrt(x^4-1) is x<=-1\lor x>= 1