What is the domain of log_{10}(2x^2-5x+3) ?

The domain of log_{10}(2x^2-5x+3) is x 3/2

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domain of log_{10}(2x^2-5x+3)

domain

lo g_{10} (2 x^{2} - 5 x + 3)

x < 1 or x > \frac{3}{2}

Interval Notation

(- \infty, 1) \cup (\frac{3}{2}, \infty)

Solution steps

Find positive values for logs:

x < 1 or x > \frac{3}{2}

The function domain

x < 1 or x > \frac{3}{2}

1 + 8^{- x}

y = 2 (2)^{x + 4} - 1

y = ∣ x ∣

f (x) = \frac{x + 1}{2 x ^{2} + 7 x - 9}

f (x) = \frac{2}{2 x + 6}

What is the domain of log_{10}(2x^2-5x+3) ?
The domain of log_{10}(2x^2-5x+3) is x<1\lor x> 3/2