What is the domain of y=xsqrt(x^2-2) ?

The domain of y=xsqrt(x^2-2) is x = sqrt(2)

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domain of y=xsqrt(x^2-2)

domain

y = x x^{2} - 2

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

+ x - 2

f (x) = \frac{1}{x + 7} + 9

f (x) = \frac{1}{2 x} \cdot \frac{x}{x - 1}

f (x) = \frac{x ^{2} - 2 x}{x - 3}

3 lo g_{10} (x - 3) + 4

What is the domain of y=xsqrt(x^2-2) ?
The domain of y=xsqrt(x^2-2) is x<=-sqrt(2)\lor x>= sqrt(2)