What is the domain of (8x)/(x^2-64) ?

The domain of (8x)/(x^2-64) is x 8

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domain of (8x)/(x^2-64)

domain

\frac{8 x}{x ^{2} - 64}

x < - 8 or - 8 < x < 8 or x > 8

Interval Notation

(- \infty, - 8) \cup (- 8, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 8

The function domain

x < - 8 or - 8 < x < 8 or x > 8

\frac{2 x - 1}{9 x + 5}

f (x) = \frac{1}{- x ^{2} + 9 x + 10}

f (x) = (x + 2)^{3} - 3

f (x) = (x + 2)^{3} - 2

3 x + 11

What is the domain of (8x)/(x^2-64) ?
The domain of (8x)/(x^2-64) is x<-8\lor-8<x<8\lor x>8