What is the domain of y=(4-x^2)/(x^2-x-6) ?

The domain of y=(4-x^2)/(x^2-x-6) is x 3

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domain of y=(4-x^2)/(x^2-x-6)

domain

y = \frac{4 - x ^{2}}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

f (x) = x e^{s i n (x)}

2 x^{2} + 4 x - 5

- x^{3} + 3 x^{2} + 24 x - 3

f (x) = 2 x^{2} - 3 x + 7

3 - x + 2

What is the domain of y=(4-x^2)/(x^2-x-6) ?
The domain of y=(4-x^2)/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3