What is the domain of f(x)=sqrt((x-2)/(x+4)) ?

The domain of f(x)=sqrt((x-2)/(x+4)) is x = 2

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domain of f(x)=sqrt((x-2)/(x+4))

domain

f (x) = \frac{x - 2}{x + 4}

x < - 4 or x \geq 2

Interval Notation

(- \infty, - 4) \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x < - 4 or x \geq 2

Find undefined (singularity) points:

x = - 4

Combine real regions and undefined points for final function domain

x < - 4 or x \geq 2

2 5^{x - 4} + 4

y = (x + 1)^{2} - 2

2 x^{2} - 8 x + 8

f (x) = \frac{( x + a )}{x} - a

f (x) = \frac{x + 5}{x + 1}

What is the domain of f(x)=sqrt((x-2)/(x+4)) ?
The domain of f(x)=sqrt((x-2)/(x+4)) is x<-4\lor x>= 2