What is the domain of y=sqrt((x^2)/4-1) ?

The domain of y=sqrt((x^2)/4-1) is x = 2

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domain of y=sqrt((x^2)/4-1)

domain

y = \frac{x ^{2}}{4} - 1

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = \frac{y ^{2}}{36} - \frac{x ^{2}}{25} = 1

y = \frac{5}{x - 2}

y = \frac{5}{x - 3}

\frac{1 x cos ( 2 x )}{2}

f (x) = \frac{1}{4} (4)^{x}

What is the domain of y=sqrt((x^2)/4-1) ?
The domain of y=sqrt((x^2)/4-1) is x<=-2\lor x>= 2