What is the domain of f(x)=sqrt(x^2+4x-12) ?

The domain of f(x)=sqrt(x^2+4x-12) is x = 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^2+4x-12)

domain

f (x) = x^{2} + 4 x - 12

x \leq - 6 or x \geq 2

Interval Notation

(- \infty, - 6] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 2

The function domain

x \leq - 6 or x \geq 2

g (x) = \frac{x + 7}{x ^{2} - 49}

f (x) = lo g_{\frac{1}{4}} (x^{2} - 4 x + 4)

5 - 2 x^{2}

f (x) = \frac{2 x - 6}{x ^{2} - 6 x}

What is the domain of f(x)=sqrt(x^2+4x-12) ?
The domain of f(x)=sqrt(x^2+4x-12) is x<=-6\lor x>= 2