What is the domain of f(x)=sqrt(4+2x)+1 ?

The domain of f(x)=sqrt(4+2x)+1 is x>=-2

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domain of f(x)=sqrt(4+2x)+1

domain

f (x) = 4 + 2 x + 1

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

f (x) = (x + 4)^{3} + 5

U (x) = 6 x - 1248

f (x) = \frac{( 12 x ^{2} - 27 )}{3}

\frac{5 x}{2 x - 6}

f (x) = x^{5} - x^{2}

What is the domain of f(x)=sqrt(4+2x)+1 ?
The domain of f(x)=sqrt(4+2x)+1 is x>=-2