What is the domain of (x^2)/((x-4)(x+3)(x-1)) ?

The domain of (x^2)/((x-4)(x+3)(x-1)) is x 4

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domain of (x^2)/((x-4)(x+3)(x-1))

domain

\frac{x ^{2}}{( x - 4 ) ( x + 3 ) ( x - 1 )}

x < - 3 or - 3 < x < 1 or 1 < x < 4 or x > 4

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 3, x = 1

The function domain

x < - 3 or - 3 < x < 1 or 1 < x < 4 or x > 4

h (t) = \frac{cos ^{2} ( t )}{1 - t ^{2}}

f (x) = 2^{x + 3} - 1

f (x) = 24 - 6 x

- \frac{4}{x ^{2}}

- 3 - 3 x - x^{2}

What is the domain of (x^2)/((x-4)(x+3)(x-1)) ?
The domain of (x^2)/((x-4)(x+3)(x-1)) is x<-3\lor-3<x<1\lor 1<x<4\lor x>4