What is the domain of sqrt(2x^2-7) ?

The domain of sqrt(2x^2-7) is x = sqrt(7/2)

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domain of sqrt(2x^2-7)

domain

2 x^{2} - 7

x \leq - \frac{7}{2} or x \geq \frac{7}{2}

Interval Notation

(- \infty, - \frac{7}{2}] \cup [\frac{7}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{7}{2} or x \geq \frac{7}{2}

The function domain

x \leq - \frac{7}{2} or x \geq \frac{7}{2}

arcsin (2 cos (x))

\frac{4 - 11 x}{4 - 2 x}

g (x) = - lo g_{10} (2) (x + 4)

x + \frac{a ^{2}}{x}

f (x) = \frac{8 x}{( 1 - x - 3 )}

What is the domain of sqrt(2x^2-7) ?
The domain of sqrt(2x^2-7) is x<=-sqrt(7/2)\lor x>= sqrt(7/2)