What is the domain of f(x)=sqrt(2t-3) ?

The domain of f(x)=sqrt(2t-3) is t>= 3/2

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domain of f(x)=sqrt(2t-3)

domain

f (x) = 2 t - 3

t \geq \frac{3}{2}

Interval Notation

[\frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

t \geq \frac{3}{2}

The function domain

t \geq \frac{3}{2}

\frac{x}{18 x ^{2} - 33 x - 40}

f (x) = x + 6 - 8

sin (arccos (x - 1))

f (x) = - x^{2} + 8 x - 8

f (x) = \frac{( x 5 ^{x} )}{5 ^{(x + 3)} - 6}

What is the domain of f(x)=sqrt(2t-3) ?
The domain of f(x)=sqrt(2t-3) is t>= 3/2