What is the domain of f(x)=ln(y^2-1) ?

The domain of f(x)=ln(y^2-1) is y 1

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domain of f(x)=ln(y^2-1)

domain

f (x) = ln (y^{2} - 1)

y < - 1 or y > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

y < - 1 or y > 1

The function domain

y < - 1 or y > 1

4 x + 1

f (x) = - 3 x + 5 - x - 1

f (x) = 900 cos (2 x) + 800

h (x) = lo g_{\frac{1}{2}} (∣ x ∣)

x = 4

What is the domain of f(x)=ln(y^2-1) ?
The domain of f(x)=ln(y^2-1) is y<-1\lor y>1