What is the domain of f(x)=sqrt(8ax+1) ?

The domain of f(x)=sqrt(8ax+1) is x>=-1/(8a)

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domain of f(x)=sqrt(8ax+1)

domain

f (x) = 8 a x + 1

x \geq - \frac{1}{8 a}

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{8 a}

The function domain

x \geq - \frac{1}{8 a}

f (x) = \frac{x + 4}{x ^{2} + 6 x - 27}

f (x) = \frac{8 x}{9 x - 7}

f (x) = \frac{x - 7}{x ^{2} - x - 42}

\frac{1}{2} x

f (x) = \frac{1}{3 x ^{2} + 4}

What is the domain of f(x)=sqrt(8ax+1) ?
The domain of f(x)=sqrt(8ax+1) is x>=-1/(8a)