What is the domain of (2x^2)/(x+1) ?

The domain of (2x^2)/(x+1) is x -1

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domain of (2x^2)/(x+1)

domain

\frac{2 x ^{2}}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = ln (\frac{x + 4}{4 x - 16})

\frac{cos ( t ^{2} )}{1 - e ^{t}}

- \frac{28}{x}

\frac{2 x}{7 x - 9}

f (x) = - 1 (3)^{x - 3} + 2

What is the domain of (2x^2)/(x+1) ?
The domain of (2x^2)/(x+1) is x<-1\lor x>-1