What is the domain of y= 1/(sqrt(8^2-4-2)) ?

The domain of y= 1/(sqrt(8^2-4-2)) is -infinity <y<infinity

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domain of y= 1/(sqrt(8^2-4-2))

domain

y = \frac{1}{8 ^{2} - 4 - 2}

- \infty < y < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < y < \infty

f (x) = 2 csc (3 x - π) + 1

lo g_{10} (x + 3) + 1

f (x) = 2 x^{2} + 5 x + 3

f (x) = \frac{6}{6 x - 2}

- \frac{- x}{2}

What is the domain of y= 1/(sqrt(8^2-4-2)) ?
The domain of y= 1/(sqrt(8^2-4-2)) is -infinity <y<infinity