What is the domain of e^{pi/2}-e^{arctan(1+x^2)} ?

The domain of e^{pi/2}-e^{arctan(1+x^2)} is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of e^{pi/2}-e^{arctan(1+x^2)}

domain

e^{\frac{π}{2}} - e^{a r c t a n (1 + x^{2})}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 2 x^{2} + 5 x - 6

f (x) = \frac{3 x ^{2} - 8 x - 3}{x - 3}

f (x) = \frac{x ^{2} + 6 x + 8}{x + 4}

f (x) = arcsin (2 - 4 x^{2})

f (x) = 5^{x} + 6

What is the domain of e^{pi/2}-e^{arctan(1+x^2)} ?
The domain of e^{pi/2}-e^{arctan(1+x^2)} is -infinity <x<infinity