What is the domain of f(x)= 9/(sqrt(x-5)) ?

The domain of f(x)= 9/(sqrt(x-5)) is x>5

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domain of f(x)= 9/(sqrt(x-5))

domain

f (x) = \frac{9}{x - 5}

x > 5

Interval Notation

(5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 5

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

x > 5

f (x) = - 2 - 3 ln (x - 2)

ln (2 x + 8)

f (x) = \frac{( x + 3 ) ^{2}}{x ( x + 4 ) ( x - 2 )}

\frac{7 x + 9}{x ^{4} + 16}

f (x) = lo g_{5} (x - 6) + 2

What is the domain of f(x)= 9/(sqrt(x-5)) ?
The domain of f(x)= 9/(sqrt(x-5)) is x>5