What is the domain of sqrt(9+ln(x)) ?

The domain of sqrt(9+ln(x)) is x>= 1/(e^9)

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domain of sqrt(9+ln(x))

domain

9 + ln (x)

x \geq \frac{1}{e ^{9}}

Interval Notation

[\frac{1}{e ^{9}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{9}}

The function domain

x \geq \frac{1}{e ^{9}}

g (x) = \frac{a - 3 x}{2 x - e}

f (x) = \frac{x + 8 + x - 2}{6}

f (x) = \frac{x + 4}{x - 3}

(3 x - 3)^{2}

\frac{x ^{2} + x - 42}{x ^{2} - x - 30}

What is the domain of sqrt(9+ln(x)) ?
The domain of sqrt(9+ln(x)) is x>= 1/(e^9)