What is the domain of (e^x+sin(x)-1)/(ln(x+1)) ?

The domain of (e^x+sin(x)-1)/(ln(x+1)) is -1 0

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domain of (e^x+sin(x)-1)/(ln(x+1))

domain

\frac{e ^{x} + sin ( x ) - 1}{ln ( x + 1 )}

- 1 < x < 0 or x > 0

Interval Notation

(- 1, 0) \cup (0, \infty)

Solution steps

Find positive values for logs:

x > - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 < x < 0 or x > 0

f (x) = \frac{1 0 ^{x}}{100000} + 1

f (x) = \frac{1}{1 0 ^{x}}

- x^{2} + 3 x

f (x) = 2 cos (y) - 1

\frac{x ^{2} + 5 x + 6}{x + 2}

What is the domain of (e^x+sin(x)-1)/(ln(x+1)) ?
The domain of (e^x+sin(x)-1)/(ln(x+1)) is -1<x<0\lor x>0