What is the domain of f(x)=((sqrt(x+8)))/(x-8) ?

The domain of f(x)=((sqrt(x+8)))/(x-8) is -8 8

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domain of f(x)=((sqrt(x+8)))/(x-8)

domain

f (x) = \frac{( x + 8 )}{x - 8}

- 8 \leq x < 8 or x > 8

Interval Notation

[- 8, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 8 \leq x < 8 or x > 8

f (x) = \frac{1}{ln ( x )}

(x - 2)^{2} + 5

(x - 2)^{2} + 2

(x - 2)^{2} - 4

f (x) = lo g_{10} (∣ 3 x + 6 ∣)

What is the domain of f(x)=((sqrt(x+8)))/(x-8) ?
The domain of f(x)=((sqrt(x+8)))/(x-8) is -8<= x<8\lor x>8