What is the domain of f(x)= 1/((y-2)(y-8)) ?

The domain of f(x)= 1/((y-2)(y-8)) is y 8

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domain of f(x)= 1/((y-2)(y-8))

domain

f (x) = \frac{1}{( y - 2 ) ( y - 8 )}

y < 2 or 2 < y < 8 or y > 8

Interval Notation

(- \infty, 2) \cup (2, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

y = 2, y = 8

The function domain

y < 2 or 2 < y < 8 or y > 8

\frac{1 - 2 x}{\frac{x}{x ^{2} - 1}}

f (x) = lo g_{4} (\frac{1}{4} x - 12)

ln (3 x + 4)

f (x) = \frac{3 x + 2}{x - 2}

f (x) = x + 1, x < - 1

What is the domain of f(x)= 1/((y-2)(y-8)) ?
The domain of f(x)= 1/((y-2)(y-8)) is y<2\lor 2<y<8\lor y>8